(x+4)(x^2+4x+3)=28(x+3)

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Solution for (x+4)(x^2+4x+3)=28(x+3) equation: 



(x+4)(x^2+4x+3)=28(x+3)

We move all terms to the left:

(x+4)(x^2+4x+3)-(28(x+3))=0



We calculate terms in parentheses: -(28(x+3)), so:

28(x+3)

We multiply parentheses

28x+84

Back to the equation:

-(28x+84)



We get rid of parentheses

(x+4)(x^2+4x+3)-28x-84=0

We add all the numbers together, and all the variables

-28x+(x+4)(x^2+4x+3)-84=0

We move all terms containing x to the left, all other terms to the right

-28x+(x+4)(x^2+4x+3)=84

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